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The Figure Shows A Circular Region Of Radius

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The flux encircled by a concentric circle of radius r is given by, where and t is in seconds. The self-inductance of the coil is. Reason: Work done in a closed path in the induced electric field is non-zero. The figure shows a circular region of radius in which an electric flux is directed out of the plane of the page. The induced electric field at a distance r from the centre is. Localid="1663150013317". A) What is the magnitude of the magnetic field at radial distance? How much is the current in the circuit in steady state?

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At what depth is the bubble below the surface of the liquid? The force is: Laws of Motion. We need your help to maintenance this website. Ds denotes small elemental length/distance. B) What is the current in the wires attached to the plates? Get premium membership. Practice over 30000+ questions starting from basic level to JEE advance level. Figure shows a circular region of radius R in which uniform magnetic field B exists. As i. e., then the is taken as unity, so the equation is. In terms of resistance and time, the dimensions of ratio of the permeability and permittivity is: Physical World, Units and Measurements. The formula is as follows: Where, is the magnetic field, is the flux. Assertion: When a piece of non-metal and a metal are dropped from the same height near the surface of the earth, the non-metallic piece will reach the ground first.

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Non-uniform along its length. The space between the plates of a parallel plate capacitor is filled with a 'dielectric' whose 'dielectric constant' varies with distance as per the relation: The capacitance, of this capacitor, would be related to its 'vacuum' capacitance as per the relation: Electrostatic Potential and Capacitance. What are the resistance of armature and induced e. m. f.? Ample number of questions to practice Figure shows a circular area of radius R where a uniform magnetic fieldis going into the plane of paper and increasing in magnitude at a constant rate. The magnetic flux linked with a coil varies with time as, where is in weber and t is in seconds.

Figure Shows Circular Region Of Radius R

70 V. A uniform rod rotates in a uniform magnetic field B (perpendicular to its length) about its one of the end with constant angular velocity. HR Interview Questions. Figure 32-27 shows a closed surface. If the velocity of conductor becomes double, the induced current will be. The electric field produced is. Reason: Induced current in metal will decrease the acceleration.

The Figure Shows A Circular Region Of Radius X

A body of mass under the action of constant force has velocity at as m/s and at as m/s. Give tests to analyze your progress and evaluate where you stand in terms of your JEE preparation. Effective Resume Writing. Updated on 16-Mar-2023 12:33:34.

In A Cylindrical Region Of Radius R

We are a non-profit group that run this website to share documents. Current Electricity. C) Perpendicular to magnetic field lines. 5 s, the average induced emf in the coil is 1 volt. Both assertion and reason are false statements. The width of the pavement is x meters as shown. Two plates (as in Fig. Assertion: Self-inductance is called the inertia of electricity. D) Parallel to magnetic field lines, with the south pole pointing in the direction of the field. Assertion: Iron loss is minimized by using a laminated core. The Question and answers have been prepared. Access over 500+ hours of video lectures 24*7, covering complete syllabus for JEE preparation. Test Series/Daily assignments.

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Assertion is a true statement but the reason is false. 5 s. 3. t = 3 s. 4. t = 5 s. Choke coil works on the principle of. Live Doubt Clearing Session. What are the (a) magnitude and (b) direction (inward or outward) of the magnetic flux through the curved part of the surface? 1. for all values of r. 2. for all values of r. 3. for rR and for rR. Thank you for interesting in our services. When it delivers 30A the potential is 120V. Defined & explained in the simplest way possible. The JEE exam syllabus. And access revision papers with marking schemes, video lessons and live classes. The induced current is zero at: 1. t = 0. Solving further, - ∫ ds = 2πr as it will cover whole length of the circle i. e. circumference.

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Developer's Best Practices. Solution: Questions from Electromagnetic Induction. For JEE 2023 is part of JEE preparation. Answer: Explanation: As given the Magnetic field is increasing at a rate of dB/dt, therefore the magnetic field is not constant. National Mock Tests. UPSC IAS Exams Notes. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

If the magnetic flux linked with the primary coil is given by where is in weber, is time in second and is a constant, then the output voltage across the secondary coil is: Questions from JEE Main 2014. Along the flat bottom face, a magnetic flux 0. Can you explain this answer?. Hence, we got the value of electric field. For a non-uniform electric field, we use equation 32-3 for finding the magnetic field inside the circle and outside the circle.